Age Game

[Pidgeot]

Right. Every user has an age. So, you have to multiply/add/divide/subtract the number above using your age number. Eg.


User 1: 0+12= 12

User 2: 12x10= 120

User 3: 120/10= 12


Let's begin.


0-12= -12


PS. You can use a calculator.

 

[Vasili]

-12X12=-144

 

[0_o o_0]

144/12=12

 

[Pidgeot]

144-12= 132

 

[pikalax]

132 + 18 = 150 (I was going to divide, but I assume only integers are allowed... -_-)

 

[Vasili]

12X12= 144

The number was -144.
150X12
=1800

Awww.. I wanted to do the Coeffiecent!

 

[Mijzelffan]

1800^16 = 2075258708292324556800 (really)

 

[pikalax]

2075258708292324556800 is wrong, it's 1.21439531096594251776 X 10^52.

(1.21439531096594251776 X 10^52)/18=6.746640616477458432 X 10^50

 

[Rayne]

-12X12=-144

144/12=12

<< Forgot to carry the negative through there guys.

Not that it's really serious or anything. [Although Doofenshmirtz's result would have been -156 instead of (-)132]

But that's all fine so just carry on.


I take the 22nd root of 6.746640616477458432 X (10^50)

or that's just (6.746640616477458432 X (10^50))^(1 / 22)

= 204.368083

 

[Mijzelffan]

16tangens(204.3680830) = 7.247177677

 

[MajorTom]

7.247177677 x 222

1608.873444294

 

[pikalax]

You're 222 years old? Wow...

1608.873444294/18 = 89.38185802

 

[Rayne]

ln(89.38185802)+22 =~ 26.5

7.247177677 x 222

7.247177677 x 222

222

Someone needs to contact Guinness. And ask for a couple rounds of pints while we're at it.

 

[Mijzelffan]

16π x 26.5 ≈ 1332

 

[Vasili]

1332/12
111
Thank you Mijzelffan, i thought for a second we would need a ton of 10 year olds.

 

[Rayne]

XD I've been looking for an approximately equals ANSI code! I could never find it since I couldn't type it.

Also PI being constant is a third variable in the equation. Does that mean you've become quite circumferential in your years D: I kid.

111*22=2442

Palindrome!

 

[Showsni]

I'd do the 23rd root, but then we'd get 23 different answers...

2442 + 23 = 2465

Edit: Third time lucky!