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In a deck
- Thread starter Bloop
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I'm not very good at the card game but I think you should have 4 Lilipups, 3-4 Herdiers, and 3 Stoutland. You need 4 Lilipups so that you will have extras when they faint. (destroyed, gone, whatever you call it). And also for the Hediers. But i'm not sure but when I got this deck, it had like 4 and 3 of the same cards.
~ Hope this helps.
~ Hope this helps.
Palbert6393
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It depends on how important it is to the deck, and if you use rare candies.
In the future, please use the simple questions thread.
In the future, please use the simple questions thread.
Palbert6393
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probably 2-2-1 or 2-1-1
Politoed666
#winning
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In a deck based around Stoutland, you'd want a 4-2-4 or a 3-1-3, with four Rare Candy.
This will probably be really silly to a lot of people, but I only ever have one of each in a deck. I only ever battle either friends or family, so I include everything in my decks from cards from the Base Set to cards from the Black & White Set. I much prefer to use as many cards as possible, to see as many as possible and so only ever use one of each - like, I'll only put in one Lillipup, one Herdier and one Stoutland so that I have as much room for other Pokémon as possible.
I know it may seem stupid and bad planning, possibly even making it more difficult than it needs to be, but I look at it from this perspective - my brother used to always do his decks by, for example, four Nidoran (M), two Nidorino and one Nidoking (all Base). Using the same number of cards, I would have, for example, one Nidoran (M), one Nidorino, one Nidoking, one Nidoran (F), one Nidorina, one Nidoqueen and one Chansey (all Base/Jungle). Looking at it in those terms, I have a greater chance of drawing either a new Basic Pokémon or an Evolution of something I already have out, whereas he has a greater chance of pulling out another Nidoran (M). I've seen a situation where he has sitting on his Bench, three Nidoran (M) and one Nidoking. To me, that's kinda useless. Especially if you multiple the chances of what you're gonna draw - say if each of you have 20 Pokémon per deck - that's almost half of his taken up by one Evolutionary line alone and say, hypothetically, his other cards are three Aron, two Lairon, one Aggron, four Pikachu , two Raichu and two Base Chansey - 20. While he has a chance of getting out two Nidoking and two Aggron, he has a greater chance of winding up with a full Bench of Pokémon that he's rendered useless by leaving himself room for only two fully Evolved Pokémon and four basics (or mid-stagers), whereas I would have the potential to have an entire team of six fully Evolved Pokémon and thereby have a greater chance of winning.
I know that was a bit of a long-winded off-topic response, but I honestly think the best way to go is 1-1-1 because you're gonna increase your chances of winning that way in my opinion.
I know it may seem stupid and bad planning, possibly even making it more difficult than it needs to be, but I look at it from this perspective - my brother used to always do his decks by, for example, four Nidoran (M), two Nidorino and one Nidoking (all Base). Using the same number of cards, I would have, for example, one Nidoran (M), one Nidorino, one Nidoking, one Nidoran (F), one Nidorina, one Nidoqueen and one Chansey (all Base/Jungle). Looking at it in those terms, I have a greater chance of drawing either a new Basic Pokémon or an Evolution of something I already have out, whereas he has a greater chance of pulling out another Nidoran (M). I've seen a situation where he has sitting on his Bench, three Nidoran (M) and one Nidoking. To me, that's kinda useless. Especially if you multiple the chances of what you're gonna draw - say if each of you have 20 Pokémon per deck - that's almost half of his taken up by one Evolutionary line alone and say, hypothetically, his other cards are three Aron, two Lairon, one Aggron, four Pikachu , two Raichu and two Base Chansey - 20. While he has a chance of getting out two Nidoking and two Aggron, he has a greater chance of winding up with a full Bench of Pokémon that he's rendered useless by leaving himself room for only two fully Evolved Pokémon and four basics (or mid-stagers), whereas I would have the potential to have an entire team of six fully Evolved Pokémon and thereby have a greater chance of winning.
I know that was a bit of a long-winded off-topic response, but I honestly think the best way to go is 1-1-1 because you're gonna increase your chances of winning that way in my opinion.
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